4x^2-32x+18=0

Solution for 4x^2-32x+18=0 equation:

4x^2-32x+18=0

a = 4; b = -32; c = +18;
Δ = b2-4ac
Δ = -322-4·4·18
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{46}}{2*4}=\frac{32-4\sqrt{46}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{46}}{2*4}=\frac{32+4\sqrt{46}}{8}
$